Gnuplot, l'amélioration de terrain fonction escalier

Question

je le script suivant:

set xlabel "y" 
set ylabel "rw[j]" 
set title "P-D diagram" 
set xzeroaxis 
unset key 

plot [0.5:1] \ 
-5.71429*x title "L[-5]" linetype 1, \ 
-4.28571*x title "U[-5]" linetype 3, \ 
-4.71429*x title "L[-4]" linetype 1, \ 
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-2.28571*x title "U[-3]" linetype 3, \ 
-2.71429*x title "L[-2]" linetype 1, \ 
-1.28571*x title "U[-2]" linetype 3, \ 
-1.71429*x title "L[-1]" linetype 1, \ 
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0.714286*x title "U[0]" linetype 3, \ 
0.285714*x title "L[1]" linetype 1, \ 
1.71429*x title "U[1]" linetype 3, \ 
1.28571*x title "L[2]" linetype 1, \ 
2.71429*x title "U[2]" linetype 3, \ 
2.28571*x title "L[3]" linetype 1, \ 
3.71429*x title "U[3]" linetype 3, \ 
3.28571*x title "L[4]" linetype 1, \ 
4.71429*x title "U[4]" linetype 3, \ 
4.28571*x title "L[5]" linetype 1, \ 
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pause - 1 

qui trace les éléments suivants:

Je voudrais être en mesure de tracer un escalier réelle au lieu de ces sauts, aussi Il me semble que deux lignes orange consécutives dans l'axe des y, il y a un écart delta_y, mais il ne devrait pas être comme cela étant donné que l'axe y est partitionné en intervalles contigus.

Des indices? (PS le script est généré par un programme, ma version gnuplot est 5.2)

Answer 1

Vous pouvez utiliser la fonction int pour arrondir les nombres (positifs) à l'entier suivant. En utilisant les bons facteurs, cela donne des mesures appropriées. Par exemple, vous pouvez faire ce qui suit pour tracer 5*x dans les étapes de la taille 0.31250:

rounddown(x,p) = int(x/p)*p 
plot rounddown(5*x,0.31250) 

Notez que pour les basses résolutions, il peut être nécessaire d'augmenter le nombre d'échantillons, par exemple comme suit:

set samples 10000