Trouver la phrase et le paragraphe avec Python

Question

Je suit le format des données:

[1956, Jon's story, He sold his soul in 1987, 200] 
[1960, Mary's story, "She liked her soul, but decided to sold it anyway.", 250] 
[1963, "Alice and Peter story, with a twist", "Peter said "Your soul is mine!" and tried to sold it, but Alice had no soul and killed him.", 500] 

Je veux partager ce à

[1956, 1960, 1963] 
['Jon's story', 'Mary's story','Alice and Peter story, with a twist'] 
['He sold his soul in 1987','She liked her soul, but decided to sold it anyway.','Peter said "Your soul is mine!" and tried to sold it, but Alice had no soul and killed him.'] 
[200,250,500] 

Jusqu'à présent, je l'ai fait

import re 
data = [[1956, "Jon's story", "He sold his soul in 1987", 200], 
     [1960, "Mary's story", "She liked her soul, but decided to sold it anyway.", 250], 
     [1963, "Alice and Peter story, with a twist", "Peter said 'Your soul is mine!' and tried to sold it, but Alice had no soul and killed him.", 500]] 
for row in data: 
    line = str(row) 
    sentence = re.split(r',', line) 

Mais de cette façon, il prend en compte la séparation des virgules à l'intérieur de "". Comment puis-je l'éviter?

Answer 1

Donc, cela peut être résolu en utilisant zip au lieu de re, regardez ci-dessous au code et voir comment cela fonctionne. m4, m3, m2, m1 seront les listes avec les valeurs dont vous avez besoin

data = [[1956, "Jon's story", "He sold his soul in 1987", 200], 
    [1960, "Mary's story", "She liked her soul, but decided to sold it anyway.", 250], 
    [1963, "Alice and Peter story, with a twist", "Peter said 'Your soul is mine!' and tried to sold it, but Alice had no soul and killed him.", 500]] 
    m4, m3 ,m2,m1 = map(list, zip(*data))