en comparant plusieurs chaînes caractère par caractère et en produisant le chevauchement?

Question

rubis

j'ai les suivantes

p = 0 
[s1.size,s2.size].max.times { |c| if s1[c] == s2[c]; p = c; else break; end }; 
matched_part = s1[0..p] 

mais je ne sais pas comment je peux cela pour plusieurs chaînes (plus de 2) en même temps.

Answer 1

class String 
    def self.overlap(first,second,*others) 
    s1 = first 
    others = [second] + others 
    others.each do |s2| 
     p = 0 
     s1.length.times { |c| if s1[c] == s2[c] then p = c else break end } 
     s1 = s1[0..p] 
    end 
    s1 
    end 
end 

puts String.overlap "marry had a little lamb", "marry had a bug dog", "marry had a cat", "marry had a bird OUT:", "marry had something" #=> marry had 

Answer 2

D'accord, comment ça?

class String 
    def self.overlap(s1,s2,*strings) 
    strings += [s2] 
    strings.min { |s| s.size }.size.times do |n| 
     return s1[0,n] unless strings.all? { |string| s1[n]==string[n] } 
    end 
    s1 
    end 
end 

Answer 3

en une ligne:

strings[0].slice(0,(0...strings[0].size).find {|i| strings.map {|s| s[i..i]}.uniq.size > 1})