Je suis assez nouveau à SQLAlchemy, ou même la programmation de base de données, peut-être ma question est trop simple. Maintenant, j'ai deux classes/table:Starter question de style déclaratif SQLAlchemy relation()
class User(Base):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
name = Column(String(40))
...
class Computer(Base):
__tablename__ = 'comps'
id = Column(Integer, primary_key=True)
buyer_id = Column(None, ForeignKey('users.id'))
user_id = Column(None, ForeignKey('users.id'))
buyer = relation(User, backref=backref('buys', order_by=id))
user = relation(User, backref=backref('usings', order_by=id))
Bien sûr, il ne peut pas fonctionner. Ceci est le backtrace:
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/state.py", line 71, in initialize_instance
fn(self, instance, args, kwargs)
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/mapper.py", line 1829, in _event_on_init
instrumenting_mapper.compile()
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/mapper.py", line 687, in compile
mapper._post_configure_properties()
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/mapper.py", line 716, in _post_configure_properties
prop.init()
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/interfaces.py", line 408, in init
self.do_init()
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/properties.py", line 716, in do_init
self._determine_joins()
File "/Library/Python/2.6/site-packages/SQLAlchemy-0.5.8-py2.6.egg/sqlalchemy/orm/properties.py", line 806, in _determine_joins
"many-to-many relation, 'secondaryjoin' is needed as well." % (self))
sqlalchemy.exc.ArgumentError: Could not determine join condition between parent/child tables on relation Package.maintainer. Specify a 'primaryjoin' expression. If this is a many-to-many relation, 'secondaryjoin' is needed as well.
Il y a deux clés étrangères en classe informatique, de sorte que la relation() ne peut pas déterminer appels que l'on doit être utilisé. Je pense que je dois utiliser des arguments supplémentaires pour le spécifier, non? Et comment? Merci
merci pour vos conseils. La faute de frappe a été corrigée et Backtrace a été ajouté. – jfding
merci, problème résolu. – jfding