comment ouvrir une application à partir du widget dans Android?

Question

lorsque nous cliquons sur le widget à ce moment-là, j'ai besoin d'ouvrir un écran d'activité (ou une application) .Comment faire?

Answer 1

Vous devez définir un onClickpendingIntent sur votre widget

Intent intent = new Intent(context, ExampleActivity.class); 
PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, intent, 0); 
// Get the layout for the App Widget and attach an on-click listener to the button 
RemoteViews views = new RemoteViews(context.getPackageName(),R.layout.appwidget_provider_layout); 
views.setOnClickPendingIntent(R.id.button, pendingIntent); 

Check this out

Processing more than one button click at Android Widget

Answer 2

Les pages de développeurs Android pour App Widgets a des informations et un exemple complet faisant exactement ceci: http://developer.android.com/guide/topics/appwidgets/index.html

Answer 3

Incluez ce code dans la méthode onUpdate() de la classe WidgetProvider.

for(int j = 0; j < appWidgetIds.length; j++) 
{ 
    int appWidgetId = appWidgetIds[j]; 

    try { 
     Intent intent = new Intent("android.intent.action.MAIN"); 
     intent.addCategory("android.intent.category.LAUNCHER"); 

     intent.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION); 
     intent.setComponent(new ComponentName("your Application package", 
      "fully qualified name of main activity of the app")); 
     PendingIntent pendingIntent = PendingIntent.getActivity(
      context, 0, intent, 0); 
     RemoteViews views = new RemoteViews(context.getPackageName(), 
      layout id); 
     views.setOnClickPendingIntent(view Id on which onclick to be handled, pendingIntent); 
    appWidgetManager.updateAppWidget(appWidgetId, views); 
    } catch (ActivityNotFoundException e) { 
      Toast.makeText(context.getApplicationContext(), 
        "There was a problem loading the application: ", 
        Toast.LENGTH_SHORT).show(); 
    } 

}