Comment sumIf une somme

Question

Je suis en train d'obtenir une « dérogation totale », mais seulement la somme si l'agent = x, y ou z

SELECT 
    DISTINCT("public"."rdf_dean"."agent_name") AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides", 
    SUM overrides IF agent_name = x OR agent_name = y OR agent_name = z 

FROM  "public"."rdf_dean" 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
GROUP BY agent_name 

Answer 1

Si vous voulez avoir les deux agrégats pour toutes les lignes et pour certains que vous pouvez utiliser FILTRE (https://www.postgresql.org/docs/9.4/static/sql-expressions.html):

SELECT 
    "public"."rdf_dean"."agent_name" AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides", 
    SUM("public"."rdf_dean"."paidcomm" *.1) 
     FILTER (WHERE agent_name = x OR agent_name = y OR agent_name = z) 
     AS "Partial Overrides", 
FROM  "public"."rdf_dean" 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
GROUP BY agent_name 

Answer 2

Comme je l'ai bien compris votre demande, vous devez résumer sur les totaux seulement dans l'agent est le cas x, y, z

donc, soit requête imbriquée:

SELECT "Agent", sum("Overrides") 
FROM 
(
SELECT 
    "public"."rdf_dean"."agent_name" AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides" 
FROM  "public"."rdf_dean" 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
GROUP BY agent_name 
) as data 
WHERE 
data."Agent" in (x, y, z) 

Ou

SELECT 
    "public"."rdf_dean"."agent_name" AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides" 
FROM  "public"."rdf_dean" 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
AND "public".rdf_dean.agent_name in (x, y, z) 
GROUP BY agent_name 

Ou si vous avez besoin d'avoir les deux, payé à l'agent et remplace uniquement par des agents

SELECT 
    "public"."rdf_dean"."agent_name" AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides", 
    (SELECT SUM("public"."rdf_dean"."paidcomm" *.1) 
     FROM "public"."rdf_dean" internal 
     WHERE 
     internal.agent_name = out.agent_name 
     AND 
     internal.agent_name in (x, y, z) ) AS "OverridesXYZ" 
FROM  "public"."rdf_dean" out 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
GROUP BY agent_name 

Ou vous pouvez

SELECT 
    "public"."rdf_dean"."agent_name" AS "Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.9) AS "Paid to Agent", 
    SUM("public"."rdf_dean"."paidcomm" *.1) AS "Overrides", 
    SUM(internal.paidcomm * .1) AS "OverridesXYZ" 
FROM  "public"."rdf_dean" out 
LEFT JOIN public.rdf_dean internal ON internal.agent_name = out.agent_name AND internal.agent_name in (x, y, z) 
WHERE "public"."rdf_dean"."created_date" = date(now()) 
GROUP BY agent_name