J'apprends MySQL/PHP et je suis juste essayer de se familiariser avec elle, mais je reçois cette erreur:PHP/MySQL: Simple question concernant la création de la table
« Table « Daniel.food » doesn « existe »
quand je lance ce code ...
<?php
mysql_connect("localhost", "USER", "PASSWORD") or die(mysql_error());
mysql_query("CREATE DATABASE Daniel") or die(mysql_error());
echo "Database created<br/><br/>";
mysql_select_db("Daniel") or die(mysql_error());
mysql_query("CREATE TABLE food(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
Meal VARCHAR(15),
Position VARCHAR(8)) or die(mysql_error()");
echo "Table: \"food\" created successfully<br/><br/>";
mysql_query("CREATE TABLE family(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
Position VARCHAR(15),
Age INT) or die(mysql_error()");
echo "Table: \"family\" created successfully<br/><br/>";
mysql_query("INSERT INTO food
(Meal, Position) VALUES ('Steak', 'Dad')") or die(mysql_error());
mysql_query("INSERT INTO food
(Meal, Position) VALUES ('Salad', 'Mom')") or die(mysql_error());
mysql_query("INSERT INTO food
(Meal, Position) VALUES ('Spinach Soup', '')") or die(mysql_error());
mysql_query("INSERT INTO food
(Meal, Position) VALUES ('Tacos', 'Dad')") or die(mysql_error());
mysql_query("INSERT INTO family
(Position, Age) VALUES ('Dad', '41')") or die(mysql_error());
mysql_query("INSERT INTO family
(Position, Age) VALUES ('Mom', '45')") or die(mysql_error());
mysql_query("INSERT INTO family
(Position, Age) VALUES ('Daughter', '17')") or die(mysql_error());
mysql_query("INSERT INTO family
(Position, Age) VALUES ('Dog', '')") or die(mysql_error());
echo "Values entered succussfully";
?>
Je suis impatient de voir les réponses.