Je veux calculer le temps diff entre starttime = 23: 30 et endtime = 00: 15 la diff temps est venu -23,25

Question

Je veux calculer le temps diff:

start_time = 23:30 
Finish_time = 00:15 

la diff temps est venu à la place -23,15 de 45 minutes.

mon code:

DATEDIFF(minute, Start_Time, Finish_Time) 

Answer 1

Étant donné que le type de données est Time, Sql server ne peut pas savoir vous dire l'heure de début et de fin est un autre jour.
Voici une façon de résoudre ce:

SELECT CASE WHEN Start_Time > Finish_Time THEN 
      DATEDIFF(minute, CAST(Start_Time As datetime), DATEADD(DAY, 1, CAST(Finish_Time As datetime))) 
     ELSE 
      DATEDIFF(minute, Start_Time, Finish_Time) 
     END 
FROM @T 

Si vous voulez que le résultat de retour comme time, vous pouvez le faire à la place:

SELECT CASE WHEN Start_Time > Finish_Time THEN 
      CAST(DATEADD(DAY, 1, CAST(Finish_Time As datetime)) - CAST(Start_Time As datetime) as time) 
     ELSE 
      CAST(CAST(Finish_Time As datetime) - CAST(Start_Time As datetime) as time) 
     END 
FROM @T 

See live demo on rextester

Voici une façon d'obtenir les valeurs décimales, où le côté droit de la virgule décimale est les heures et le côté gauche les minutes:

SELECT CAST(
      REPLACE(
        CONVERT (char(5), 
           CASE WHEN Start_Time > Finish_Time THEN 
           CAST(DATEADD(DAY, 1, CAST(Finish_Time As datetime)) - CAST(Start_Time As datetime) as time) 
           ELSE 
           CAST(CAST(Finish_Time As datetime) - CAST(Start_Time As datetime) as time) 
           END 
        , 114) 
      , ':', '.') 
     as decimal(4,2)) 
FROM @T 

Dernière édition:

;WITH CTE AS 
(
    SELECT CASE WHEN Start_Time > Finish_Time THEN 
       DATEDIFF(minute, CAST(Start_Time As datetime), DATEADD(DAY, 1, CAST(Finish_Time As datetime))) 
      ELSE 
       DATEDIFF(minute, Start_Time, Finish_Time) 
      END As DiffInMinutes 
    FROM @T 
) 
SELECT ((DiffInMinutes - (DiffInMinutes % 60))/60) + CAST((DiffInMinutes % 60) as float)/60 As DiffAsDecimalHours 
FROM CTE