Je déploie une application Web restFull webservice sur weblogic 12.2.1.2 et Elle échoue

Question

Bonjour, Je dispose d'un webservice qui se déploie avant la version weblogic 12.2.1.2 mais qui n'est pas déployé sur weblogic 12.2.1.2. et jette l'erreur ci-dessous:

<Oct 11, 2017, 8:16:22,462 PM IST> <Warning> <Munger> <BEA-2156203> <A version attribute was not found in element "web-app" in the deployment descriptor /u01/xxx/xxxx/webapps/xx/WEB-INF/web.xml. A version attribute is required, but this version of the WebLogic Server will assume that the latest version is used. Future versions of WebLogic Server will reject descriptors that do not specify the Java EE version. To eliminate this warning, add an appropriate "version=" to element "web-app" in the deployment descriptor.> 
<Oct 11, 2017, 8:16:22,620 PM IST> <Warning> <JAXRSIntegration> <BEA-2192510> <Cannot add Jersey servlet for application class com.xxx.xx.xx.xxx.JerseyConfig because ApplicationPath annotation is not set on it.> 
<Oct 11, 2017, 8:16:22,621 PM IST> <Warning> <JAXRSIntegration> <BEA-2192510> <Cannot add Jersey servlet for application class org.glassfish.jersey.server.ResourceConfig because ApplicationPath annotation is not set on it.> 
<Oct 11, 2017, 8:16:22,624 PM IST> <Warning> <JAXRSIntegration> <BEA-2192510> <Cannot add Jersey servlet for application class org.glassfish.jersey.server.ResourceConfig$WrappingResourceConfig because ApplicationPath annotation is not set on it.> 
<Oct 11, 2017, 8:16:22,624 PM IST> <Warning> <JAXRSIntegration> <BEA-2192510> <Cannot add Jersey servlet for application class org.glassfish.jersey.server.ResourceConfig$RuntimeConfig because ApplicationPath annotation is not set on it.> 
<Oct 11, 2017, 8:21:37,36 PM IST> <Error> <org.glassfish.jersey.server.spring.SpringComponentProvider> <BEA-000000> <[failed to localize] none.or.multiple.beans.available(class com.xxx.xx.xx.JerseyConfig)> 

J'ai essayé avec l'attribut version dans web.xml mais ne fonctionne pas. et jeté la même erreur.

Env. Détails:

Java-1.7 & 1.8 
weblogic-12.2.1.2 
Servlet-api-2.4 

Toute aide serait apprécié ..

Mise à jour:

<?xml version="1.0" encoding="UTF-8"?> 
<web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> 


    <display-name>xxx</display-name> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>WEB-INF/applicationContext.xml 
      WEB-INF/classes/configs/*.xml 
     </param-value> 
    </context-param> 
    <!--<context-param> 
     <param-name>contextClass</param-name> 
     <param-value>com.javaetmoi.core.spring.JBoss5XmlWebApplicationContext</param-value> 
    </context-param>--> 
    <listener> 
     <listener-class>org.springframework.web.context.ContextLoaderListener 
     </listener-class> 
    </listener> 
    <servlet> 
     <servlet-name>jerseyServlet</servlet-name> 
     <servlet-class>org.glassfish.jersey.servlet.ServletContainer 
     </servlet-class> 
     <init-param> 
      <param-name>javax.ws.rs.Application</param-name> 
      <param-value>com.xx.xx.xx.JerseyConfig</param-value> 
     </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <servlet-mapping> 
     <servlet-name>jerseyServlet</servlet-name> 
     <url-pattern>/*</url-pattern> 
    </servlet-mapping> 

    <context-param> 
     <param-name>localFilesBasePath</param-name> 
     <param-value>configs</param-value> 
    </context-param> 
    <context-param> 
     <param-name>resteasy.scan</param-name> 
     <param-value>false</param-value> 
    </context-param> 
    <context-param> 
     <param-name>resteasy.scan.providers</param-name> 
     <param-value>false</param-value> 
    </context-param> 
    <context-param> 
     <param-name>resteasy.scan.resources</param-name> 
     <param-value>false</param-value> 
    </context-param> 
    <resource-ref> 
     <res-ref-name>jdbc/xxx</res-ref-name> 
     <res-type>javax.sql.DataSource</res-type> 
     <res-auth>Container</res-auth> 
    </resource-ref> 

    <resource-ref> 
     <res-ref-name>jdbc/xxx</res-ref-name> 
     <res-type>javax.sql.DataSource</res-type> 
     <res-auth>Container</res-auth> 
    </resource-ref> 

</web-app> 

Answer 1

Ceci est un exemple web.xml de Jersey exemples, noter qu'un paramètre d'initialisation qui pointe vers la Jersey Classe d'application

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 

    <filter> 
     <filter-name>org.glassfish.jersey.examples.bookstore.webapp.MyApplication</filter-name> 
     <filter-class>org.glassfish.jersey.servlet.ServletContainer</filter-class> 
     <init-param> 
      <param-name>javax.ws.rs.Application</param-name> 
      <param-value>org.glassfish.jersey.examples.bookstore.webapp.MyApplication</param-value> 
     </init-param> 
     <!-- pass to next filter if Jersey/App returns 404 --> 
     <init-param> 
      <param-name>jersey.config.servlet.filter.forwardOn404</param-name> 
      <param-value>true</param-value> 
     </init-param> 
    </filter> 
    <filter-mapping> 
     <filter-name>org.glassfish.jersey.examples.bookstore.webapp.MyApplication</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 
</web-app> 

Ceci est la classe d'application:

public class MyApplication extends ResourceConfig { 
    public MyApplication() { 
     // Resources. 
     packages(Bookstore.class.getPackage().getName()); 

     // MVC. 
     register(JspMvcFeature.class); 

     // Logging. 
     register(LoggingFilter.class); 

     // Tracing support. 
     property(ServerProperties.TRACING, TracingConfig.ON_DEMAND.name()); 
    } 
}