Aide sur plusieurs jointure requête

Question

J'ai cette requête

SELECT t1.Trans_ID 
FROM (SELECT * FROM Prune WHERE [Name]="I1") AS t1 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I2") AS t2 ON (t1.Trans_ID = t2.Trans_ID) 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I3") AS t3 ON (t1.Trans_ID = t3.Trans_ID) 

et je me suis msg d'erreur: "Erreur de syntaxe (opérateur manquant) dans l'expression de requête

'(t1.Trans_ID = t2.Trans_ID) 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I3") AS t3 ON (t1.Trans_ID = t3.Trans_ID)' 

Mais ce travail de recherche parfaitement quand je « utilise seulement 1 jointure

SELECT t1.Trans_ID 
FROM (SELECT * FROM Prune WHERE [Name]="I1") AS t1 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I2") AS t2 ON (t1.Trans_ID = t2.Trans_ID) 

quelqu'un peut dire ce qui se passe? et comment le résoudre?
Je travaille avec ms accès

Answer 1

MsAccess est parfois pleine de merde ...

Essayez cette

SELECT t1.Trans_ID 
FROM ((SELECT * FROM Prune WHERE [Name]="I1") AS t1 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I2") AS t2 ON (t1.Trans_ID = t2.Trans_ID)) 
INNER JOIN (SELECT * FROM Prune WHERE [Name]="I3") AS t3 ON (t1.Trans_ID = t3.Trans_ID) 

S'il vous plaît noter que le support supplementare juste après FROM et FERMETURES support seulement après t2.Trans_ID)

Answer 2

Essayez ceci:

SELECT t1.Trans_ID 
FROM Prune AS t1 
INNER JOIN Prune AS t2 ON t1.Trans_ID = t2.Trans_ID 
INNER JOIN Prune AS t3 ON t1.Trans_ID = t3.Trans_ID 
WHERE t1.Name = "I1" AND t2.Name = "I2" AND t3.Name = "I3"