envoi nommé Mulitpart esprit de données HttpClient

Question

J'essaie d'envoyer du contenu multipart comme un poste à un WebService en utilisant C# HttpClient

Mon code est la suivante

public string UploadDocument(Stream stream) 
{ 

    MultipartContent multipart = new MultipartContent(); 
    //multipart.Add(new StreamContent(stream), "importFile"); 
    StreamContent content = new StreamContent(stream); 
    multipart.Add(content); 

    Client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json")); 

    HttpResponseMessage response = Client.PostAsync("URL to webservice", multipart).Result; 
    string result = response.Content.ReadAsStringAsync().Result; 

    //Wirft eine Exception wenn der StatusCode nicht 200 (OK) ist. 
    response.EnsureSuccessStatusCode(); 

    return result; 


} 

J'ai besoin du contenu Stream à être nommé, comment puis-je le faire.

Je trouve Java façon de le faire, mais en C# Je ne trouve pas un paramètre « Nom »

Ici Java Exemple (voir « importFile »)

httpRequest = new HttpPostwebviewer/?action=import"); 
    // set headers 
    httpRequest.setHeader(HEADER_NAME_ACCEPT, "application/json"); 
    // prepare upload entity 
    MultipartEntityBuilder meBuilder = MultipartEntityBuilder.create(); 
    meBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE); 
    meBuilder.setCharset(Consts.UTF_8); 
    meBuilder.addPart("importFile", contentBody); 
    // build upload entity 
    HttpEntity uploadEntity = meBuilder.build(); 
    // set properties to http request 
    ((HttpPost) httpRequest).setEntity(uploadEntity); 

Answer 1

Vous pouvez utiliser System.Net.HttpWebRequest pour faire la même chose, Voici le code que j'utilise:

public static void UploadFile(string url, string file, string paramName, string contentType, NameValueCollection nvc) 
    { 
     string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x"); 
     byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n"); 
     url = handlerLocation + url; 
     HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url); 
     wr.ContentType = "multipart/form-data; boundary=" + boundary; 
     wr.Method = "POST"; 
     wr.KeepAlive = true; 
     wr.Credentials = System.Net.CredentialCache.DefaultCredentials; 

     Stream rs = wr.GetRequestStream(); 

     string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}"; 
     foreach (string key in nvc.Keys) 
     { 
      rs.Write(boundarybytes, 0, boundarybytes.Length); 
      string formitem = string.Format(formdataTemplate, key, nvc[key]); 
      byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem); 
      rs.Write(formitembytes, 0, formitembytes.Length); 
     } 
     rs.Write(boundarybytes, 0, boundarybytes.Length); 

     string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n"; 
     string header = string.Format(headerTemplate, paramName, file, contentType); 
     byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header); 
     rs.Write(headerbytes, 0, headerbytes.Length); 

     FileStream fileStream = new FileStream(file, FileMode.Open, FileAccess.Read); 
     byte[] buffer = new byte[4096]; 
     int bytesRead = 0; 
     while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0) 
     { 
      rs.Write(buffer, 0, bytesRead); 
     } 
     fileStream.Close(); 

     byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n"); 
     rs.Write(trailer, 0, trailer.Length); 
     rs.Close(); 

     WebResponse wresp = null; 
     try 
     { 
      wresp = wr.GetResponse(); 
      Stream stream2 = wresp.GetResponseStream(); 
      StreamReader reader2 = new StreamReader(stream2); 
     } 
     catch (Exception ex) 
     { 
      //WriteTrace(ex.Message); 
      if (wresp != null) 
      { 
       wresp.Close(); 
       wresp = null; 
      } 
     } 
     finally 
     { 
      wr = null; 
     } 
    }