Comment créer un tableau croisé dans PostgreSQL?

Question

CREER TEMPORAIRE TABLE

CREATE TEMP TABLE pivot(
gid SERIAL, 
zoom smallint NOT NULL, 
day timestamp with time zone NOT NULL, 
point integer NOT NULL 
); 

Mentionner les données

INSERT INTO pivot(zoom, day, point) VALUES(6,'2015-10-01',21); 
INSERT INTO pivot(zoom, day, point) VALUES(7,'2015-10-01',43); 
INSERT INTO pivot(zoom, day, point) VALUES(8,'2015-10-01',18); 
INSERT INTO pivot(zoom, day, point) VALUES(9,'2015-10-01',14); 
INSERT INTO pivot(zoom, day, point) VALUES(10,'2015-10-01',23); 
INSERT INTO pivot(zoom, day, point) VALUES(11,'2015-10-01',54); 
INSERT INTO pivot(zoom, day, point) VALUES(6,'2015-10-02',657); 
INSERT INTO pivot(zoom, day, point) VALUES(7,'2015-10-02',432); 
INSERT INTO pivot(zoom, day, point) VALUES(8,'2015-10-02',421); 
INSERT INTO pivot(zoom, day, point) VALUES(9,'2015-10-02',432); 
INSERT INTO pivot(zoom, day, point) VALUES(10,'2015-10-02',454); 
INSERT INTO pivot(zoom, day, point) VALUES(11,'2015-10-02',654); 

permet de voir si tout fonctionne jusqu'à présent:

SELECT zoom, day, point 
FROM pivot 
ORDER BY 1,2; 

Résultat:

zoom |   day   | point 
------+------------------------+------- 
    6 | 2015-10-01 00:00:00+02 | 21 
    6 | 2015-10-02 00:00:00+02 | 657 
    7 | 2015-10-01 00:00:00+02 | 43 
    7 | 2015-10-02 00:00:00+02 | 432 
    8 | 2015-10-01 00:00:00+02 | 18 
    8 | 2015-10-02 00:00:00+02 | 421 
    9 | 2015-10-01 00:00:00+02 | 14 
    9 | 2015-10-02 00:00:00+02 | 432 
    10 | 2015-10-01 00:00:00+02 | 23 
    10 | 2015-10-02 00:00:00+02 | 454 
    11 | 2015-10-01 00:00:00+02 | 54 
    11 | 2015-10-02 00:00:00+02 | 654 
(12 rows) 

C EXTENSION RÉER:

CREATE EXTENSION tablefunc; 

CROSSTAB QUERY

SELECT * FROM crosstab(
     'SELECT zoom, day, point 
     FROM pivot 
     ORDER BY 1,2' 
     ,$$VALUES ('2015-10-01'::timestamp), ('2015-10-02')$$) 
AS ct ("zoom" smallint, "2015-10-01" integer, "2015-10-02" integer); 

Résultat:

zoom | 2015-10-01 | 2015-10-02 
------+------------+------------ 
    6 |   | 
    7 |   | 
    8 |   | 
    9 |   | 
    10 |   | 
    11 |   | 
(6 rows) 

Je ne peux pas retourner les valeurs des points, la requête elle-même me donne un taches vides. Qu'est-ce que je fais mal?

Modifier

J'ai essayé de le faire dans l'autre sens, mais je suis toujours à la recherche de la réponse à la question ci-dessus.

SELECT * from crosstab (
    'select zoom, day, point 
    from pivot 
    order by 1,2', 
    'select distinct day from pivot order by 1') 
AS ct(zoom smallint, "2015-10-01" integer, "2015-10-02" integer); 

Résultat:

zoom | 2015-10-01 | 2015-10-02 
------+------------+------------ 
    6 |   21 |  657 
    7 |   43 |  432 
    8 |   18 |  421 
    9 |   14 |  432 
    10 |   23 |  454 
    11 |   54 |  654 
(6 rows) 

Answer 1

Merci à la suggestion @Abelisto à propos timestamptz, cela fonctionne:

SELECT * FROM crosstab(
     'SELECT zoom, day, point 
     FROM pivot 
     ORDER BY 1,2' 
     ,$$VALUES ('2015-10-01'::timestamptz), ('2015-10-02')$$) 
AS ct ("zoom" smallint, "2015-10-01" integer, "2015-10-02" integer);