Possible en double:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL resultAvertissement lors de l'utilisation mysql_fetch_assoc en PHP
Quand je lance ma page php, je reçois cette erreur et je ne sais pas ce qui ne va pas, quelqu'un peut-il aider? Si quelqu'un a besoin de plus d'informations, je posterai tout le code.
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in H:\Program Files\EasyPHP 2.0b1\www\test\info.php on line 16
<?PHP
$user_name = "root";
$password = "";
$database = "addressbook";
$server = "127.0.0.1";
$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);
if ($db_found) {
$SQL = "SELECT * FROM tb_address_book";
$result = mysql_query($SQL);
while ($db_field = mysql_fetch_assoc($result)) {
print $db_field['ID'] . "<BR>";
print $db_field['First_Name'] . "<BR>";
print $db_field['Surname'] . "<BR>";
print $db_field['Address'] . "<BR>";
}
mysql_close($db_handle);
}
else {
print "Database NOT Found ";
mysql_close($db_handle);
}
?>
L'ensemble du code serait probablement usefil. – Dre