Voici la définition implicite qui convertit votre Regex
en Parser
.
/** A parser that matches a regex string */
implicit def regex(r: Regex): Parser[String] = new Parser[String] {
def apply(in: Input) = {
val source = in.source
val offset = in.offset
val start = handleWhiteSpace(source, offset)
(r findPrefixMatchOf (source.subSequence(start, source.length))) match {
case Some(matched) =>
Success(source.subSequence(start, start + matched.end).toString,
in.drop(start + matched.end - offset))
case None =>
Failure("string matching regex `"+r+"' expected but `"+in.first+"' found", in.drop(start - offset))
}
}
}
adapter Il suffit:
object X extends RegexParsers {
/** A parser that matches a regex string and returns the Match */
def regexMatch(r: Regex): Parser[Regex.Match] = new Parser[Regex.Match] {
def apply(in: Input) = {
val source = in.source
val offset = in.offset
val start = handleWhiteSpace(source, offset)
(r findPrefixMatchOf (source.subSequence(start, source.length))) match {
case Some(matched) =>
Success(matched,
in.drop(start + matched.end - offset))
case None =>
Failure("string matching regex `"+r+"' expected but `"+in.first+"' found", in.drop(start - offset))
}
}
}
val t = regexMatch("""(\d\d)/(\d\d)/(\d\d\d\d)""".r) ^^ { case m => (m.group(1), m.group(2), m.group(3)) }
}
Exemple:
scala> X.parseAll(X.t, "23/03/1971")
res8: X.ParseResult[(String, String, String)] = [1.11] parsed: (23,03,1971)
Merci Daniel, fonctionne comme un charme –
Great post! Excellent! – fotNelton
C'est curieux, pourquoi ce genre de fonctionnalité ne fait pas partie de la mise en œuvre de la classe standard (bibliothèque)? Cela semble très utile, mais chaque utilisateur devrait l'implémenter lui-même ... –