enregistrements Sélectionnez le tableau que les chiffres de différents sur la base de rejoindre

Question

Je veux obtenir le nombre d'enregistrements saisis par un utilisateur dans la table différente. Le schéma de DB est:

+-----------------------+ 
| Survey Master   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| Username  |  | 
| FamilyMasterId | FK | 
+----------------+------+ 

+------------+------+ 
| Family Master  | 
+------------+------+ 
| Field  | Key | 
+------------+------+ 
| id   | PK | 
+------------+------+ 

+-----------------------+ 
| Family Detail   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| FamilyMasterId | FK | 
+----------------+------+ 

+-----------------------+ 
| Travel Master   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| FamilyDetailId | FK | 
+----------------+------+ 

+-----------------------+ 
| Travel Detail   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| TravelMasterId | FK | 
+----------------+------+ 

Je veux voir le nombre de documents créés par chaque utilisateur dans chaque table quelque chose comme ceci:

Username SurveyMaster FamilyMaster FamilyDetail TravelMaster TravelDetail 
---------- -------------- -------------- -------------- -------------- -------------- 
    User001 59    47    36    26    12    
    User002 88    76    64    42    25    
    User003 49    44    35    25    15    
    User004 77    69    55    45    37 

Après avoir examiné les liens suivants:

1. Find Records from Different Tables
2. Select count(*) from multiple tables
3. http://www.sqlines.com/mysql/how-to/join-different-tables-based-on-condition
4. http://www.informit.com/articles/article.aspx?p=30875&seqNum=5
5. SQL: Combine Select count(*) from multiple tables

j'ai pu écrire cette requête mais il donne les mêmes enregistrements dans toutes les colonnes:

SELECT USERNAME, COUNT(USERNAME) SURVEYMASTER, COUNT(USERNAME) FAMILYMASTER, COUNT(USERNAME) FAMILYDETAIL, COUNT(USERNAME) TRAVELMASTER, COUNT(USERNAME) TRAVELDETAIL FROM 
((SELECT CREATEUSER USERNAME FROM SURVEYMASTER 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID 
INNER JOIN TRAVELDETAIL TD ON TM.ID = TD.TRAVELMASTERID 
) 
) T 
GROUP BY USERNAME 
ORDER BY USERNAME 

EDIT

Voici la relation description:

1. FamilyMasterId est la clé étrangère dans Surveymaster et FamilyDetail tables.
2. FamilyDetailId est la clé étrangère dans le tableau de TravelMaster. TravelMasterId est la clé étrangère dans la table TravelDetail.

Answer 1

Cela pourrait ne pas être la solution parfaite si l'on considère la performance, mais il peut donner le résultat souhaité

SELECT sm.Username , 
     COUNT(*) SurveyMaster , 
     COUNT(FamilyMasterId) FamilyMaster , 
     fd.FamilyDetail , 
     tm.TravelMaster , 
     td.TravelDetail 
FROM SurveyMaster sm 
     JOIN (SELECT Username , 
         COUNT(fd.id) FamilyDetail 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
       GROUP BY Username 
      ) fd ON sm.Username = fd.Username 
     JOIN (SELECT Username , 
         COUNT(tm.id) TravelMaster 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
         JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId 
       GROUP BY Username 
      ) tm ON sm.Username = tm.Username 
     JOIN (SELECT Username , 
         COUNT(td.id) TravelDetail 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
         JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId 
         JOIN TravelDetail td ON tm.Id = td.TravelMasterId 
       GROUP BY Username 
      ) td ON sm.Username = td.Username 
GROUP BY sm.Username , 
     fd.FamilyDetail , 
     tm.TravelMaster , 
     td.TravelDetail;