Voici un exemple d'analyse du nom de fichier. Vous pouvez utiliser ces techniques pour analyser la version. Des notes supplémentaires sont dans les commentaires du code.
Private Function ParseXsnFileName(ByVal strTarget As String) As String
Dim strResult As String = String.Empty
'Get the location of where the .xsn extension starts.
Dim intExtensionLocation As Integer = strTarget.IndexOf(".xsn")
If intExtensionLocation >= 0 Then
'Now we will initiate a loop that iterates back character by character until we find
'the forward slash of the URL that preceedes the filename.
Dim bolStartFound As Boolean = False
Dim intCursor As Integer = intExtensionLocation
Do Until intCursor = 0 OrElse bolStartFound
If strTarget.Substring(intCursor, 1) = "/" Then
'Setting this to true exist the loop.
bolStartFound = True
End If
intCursor -= 1
Loop
If bolStartFound Then
'We found all of the pieces we need to parse out the filename.
'Add 2 because of the "intCursor -= 1" and because we don't want the/in the filename.
Dim intStartLocation As Integer = intCursor + 2
'Add 4 to StartLocation because we want the extension.
'Subtract intStartLocation from intExtensionLocation to get the length.
strResult = strTarget.Substring(intStartLocation, (intExtensionLocation - (intStartLocation + 4)))
End If
End If
Return strResult
End Function
Exemple d'utilisation:
Dim strParseThis As String = "http://servername/foldername/forms/fileNameV100.xsn"
Dim strFileName As String = ParseXsnFileName(strParseThis)
Êtes-vous juste essayer d'analyser le nom de fichier d'un 'CHAINE' ou êtes-vous en utilisant quelque chose comme' XPath'? – jradich1234
Essayez simplement d'analyser la chaîne dans la partie "nom de fichier" du chemin. –