Passer des arguments à travers timer.PerformWithDelay - Lua

Question

J'apprends la langue Lua. Je suis un peu confuse. Je souhaite passer l'argument à la fonction timer.PerformWithDelay. Voici le code que j'ai écrit:

local function animate (event) 
    gear.rotation = gear.rotation + rotateAmount; 
end 
Runtime:addEventListener("enterFrame", animate); 
------------------------------------------------ 
function reverseRotate() 
    if tonumber(rtAm) > 0 then -- here appear error: "Attempt to compare number with nil" 
     rotateAmount = rotateAmount - 1; 
    elseif tonumber(rtAm) < 0 then 
     rotateAmount = rotateAmount + 1; 
    end 
end 
------------------------------------------------ 
local buttonHandler = function (event) 
    if event.phase == "ended" then 
     local iteration = math.abs(rotateAmount); 
      if rotateAmount > 0 then 
       local rtAm = rotateAmount; 
       timer.performWithDelay(100, function() reverseRotate ("rtAm") end, 2*iteration); 
      elseif rotateAmount < 0 then 
       local rtAm = rotateAmount; 
       timer.performWithDelay(100, function() reverseRotate ("rtAm") end, 2*iteration); 
      end 
    end 
end 

Ma question est: pourquoi la variable RTAM ne passe pas à la fonction reverseRotation?

Answer 1

Vous transmettez une chaîne littérale dans votre appel au lieu de la variable. Changer

timer.performWithDelay(100, function() reverseRotate ("rtAm") end, 2*iteration); 

à

timer.performWithDelay(100, function() reverseRotate(rtAm) end, 2*iteration);