System.out.println - Erreur de syntaxe

Question

Débutant dans Java ici.

Vous essayez de comprendre pourquoi j'obtiens une erreur de syntaxe sur les deux derniers System.out.println.

J'ai essayé de déplacer mes supports, mais je me retrouve avec une boucle sans fin.

J'apprécie toute votre aide à l'avance!

---

import java.util.Scanner; 

public class GuessingGame 
{ 

    public static void main(String args []) 
    { 
     Scanner scan = new Scanner (System.in); 

     int random = (int) (Math.random()*20 +1); 
     int numberOfAttempts = 0; 
     boolean win = false; 

     while (win == false) 

      System.out.println("Guess the number (1 - 20)"); 
      int guess = scan.nextInt(); 
      numberOfAttempts++; 

      if (guess == random) 
       win = true; 
      else if (guess < random) 
       System.out.println("Your guess was low. Guess again."); 
      else 
       System.out.println("Your guess was high. Guess again."); 
    } 

      System.out.println("You guessed right! It took you guesses."); 
      System.out.println("Do you want to play again? (yes or no)"); 

} 

Answer 1

Votre ne pas ouvrir la boucle while. Vous avez besoin de crochets après le temps

while (win == false){ 
//need one at the beginning 

     System.out.println("Guess the number (1 - 20)"); 
     int guess = scan.nextInt(); 
     numberOfAttempts++; 

     if (guess == random) 
      win = true; 
     else if (guess < random) 
      System.out.println("Your guess was low. Guess again."); 
     else 
      System.out.println("Your guess was high. Guess again."); 
} //and at the end