Erreur MySQL, raison inconnue

Question

J'ai lu cette requête maintenant pendant environ 20 minutes et je ne vois pas ce qui ne va pas.

SELECT SQL_CALC_FOUND_ROWS addressbook_people.first_name, 
     addressbook_people.last_name      , 
     addressbook_people.preferred_name    , 
     addressbook_companies3.name      , 
     addressbook_people.url       , 
     addressbook_groups5.name       , 
     addressbook_people.telephone1     , 
     addressbook_people.telephone2     , 
     addressbook_people.telephone3     , 
     addressbook_people.email1      , 
     addressbook_people.email2      , 
     addressbook_people.fax1       , 
     addressbook_people.fax2       , 
     root_countries13.name       , 
     root_territories14.name       , 
     root_cities15.name        , 
     addressbook_people.address1      , 
     addressbook_people.zip_postal1     , 
     addressbook_people.po_box      , 
     root_countries19.name       , 
     root_territories20.name       , 
     root_cities21.name        , 
     addressbook_people.address2      , 
     addressbook_people.zip_postal2 
FROM  addressbook_people 
WHERE (
        (
          addressbook_people.first_name  LIKE '%a%' 
        OR  addressbook_people.last_name  LIKE '%a%' 
        OR  addressbook_people.preferred_name LIKE '%a%' 
        OR  addressbook_companies3.name  LIKE '%a%' 
        OR  addressbook_people.url   LIKE '%a%' 
        OR  addressbook_groups5.name   LIKE '%a%' 
        OR  addressbook_people.telephone1  LIKE '%a%' 
        OR  addressbook_people.telephone2  LIKE '%a%' 
        OR  addressbook_people.telephone3  LIKE '%a%' 
        OR  addressbook_people.email1   LIKE '%a%' 
        OR  addressbook_people.email2   LIKE '%a%' 
        OR  addressbook_people.fax1   LIKE '%a%' 
        OR  addressbook_people.fax2   LIKE '%a%' 
        OR  root_countries13.name    LIKE '%a%' 
        OR  root_territories14.name   LIKE '%a%' 
        OR  root_cities15.name    LIKE '%a%' 
        OR  addressbook_people.address1  LIKE '%a%' 
        OR  addressbook_people.zip_postal1 LIKE '%a%' 
        OR  addressbook_people.po_box   LIKE '%a%' 
        OR  root_countries19.name    LIKE '%a%' 
        OR  root_territories20.name   LIKE '%a%' 
        OR  root_cities21.name    LIKE '%a%' 
        OR  addressbook_people.address2  LIKE '%a%' 
        OR  addressbook_people.zip_postal2 LIKE '%a%' 
       ) 
     ) 
     LEFT JOIN addressbook_companies AS addressbook_companies3 
     ON  addressbook_people.company_id = addressbook_companies3.id 
     LEFT JOIN addressbook_groups AS addressbook_groups5 
     ON  addressbook_people.group_id = addressbook_groups5.id 
     LEFT JOIN root_countries AS root_countries13 
     ON  addressbook_people.country1 = root_countries13.id 
     LEFT JOIN root_territories AS root_territories14 
     ON  addressbook_people.territory1 = root_territories14.id 
     LEFT JOIN root_cities AS root_cities15 
     ON  addressbook_people.city1 = root_cities15.id 
     LEFT JOIN root_countries AS root_countries19 
     ON  addressbook_people.country2 = root_countries19.id 
     LEFT JOIN root_territories AS root_territories20 
     ON  addressbook_people.territory2 = root_territories20.id 
     LEFT JOIN root_cities AS root_cities21 
     ON  addressbook_people.city2 = root_cities21.id 
ORDER BY LTRIM(addressbook_people.url)DESC 
LIMIT 0, 10 

Ceci est la sortie de mon filtre pour une table de données. Donc, ne pas tenir compte du fait que je cherche comme « a »

J'utilise PHPMyAdmin, lors de l'exécution du SQL dans une requête via la console de gestion Web je reçois l'erreur suivante

1064 - Vous avez un erreur dans votre syntaxe SQL; consultez le manuel qui

correspond à votre version du serveur MySQL pour la bonne syntaxe à utiliser près « LEFT JOIN addressbook_companies AS addressbook_companies3 SUR adr » à la ligne 54

J'ai vérifié la ligne, c'est la début de mes jointures. Je ne vois pas de problème .. Quelqu'un peut-il aider s'il vous plaît? Je n'ai jamais été bon avec SQL.

Answer 1

Vous devez faire vos JOIN s avant WHERE clause