Ruby combine un tableau de hachages avec la même clé et plusieurs valeurs

Question

J'ai le tableau suivant qui est en réalité une combinaison de deux tableaux. Mon objectif est que les 2 hachages avec employeeId de 898989 puissent être combinés et que je puisse ajouter leurs comptes ensemble et changer leur type en deux. J'ai essayé le code ci-dessous qui est proche de ce que je veux, mais je perds les autres valeurs de mes hachages. Existe-t-il un moyen facile de cartographier toutes les valeurs et de faire des manipulations comme l'ajout des comptes comme je le veux?

combined = [{"@rid"=>"#-2:1", "employeeId"=> "898989", "count"=>1, :type=>"wiki" }, 
     {"@rid"=>"#-2:3", "employeeId"=> "2423213", "count"=>7, :type=>"search"}, 
     {"@rid"=>"#-2:2", "employeeId"=> "555555", "count"=>2, :type=>"search"}, 
     {"@rid"=>"#-2:5", "employeeId"=> "898989", "count"=>2, :type=>"search"}, 
     {"@rid"=>"#-2:1", "employeeId"=> "5453454", "count"=>1, :type=>"search"}, 
     {"@rid"=>"#-2:4", "employeeId"=>"987654321", "count"=>1, :type=>"search"}] 

merged_array_hash = combined.group_by { |h1| h1["employeeId"] }.map do |k,v| 
    { "employeeId" => k, :types => v.map { |h2| h2[:type] }.join(", ") } 
end 

merged_array_hash finit par être:

[{employeeId: "898989",types: "wiki, search"}, 
{employeeId: "2423213",types: "search"}, 
{employeeId: "555555",types: "search"}, 
{employeeId: "5453454",types:"search"}, 
{employeeId: "987654321",types: "search"}] 

Ce que je cherche à obtenir:

[{employeeId: "898989",type: "both", count: 2}, 
{employeeId: "2423213",type: "search", count: 7}, 
{employeeId: "555555",type: "search", count: 2}, 
{employeeId: "5453454",type:"search", count: 1}, 
{employeeId: "987654321",type: "search", count: 1}] 

Answer 1

Pas beau, mais il va faire le travail:

combined.group_by { |h1| h1["employeeId"] }.map do |k,v| 
    types = v.map { |h2| h2[:type] } 
    count = v.sum { |x| x['count'] } 

    { employeeId: k, 
    types: (types.length == 1 ? types[0] : 'both'), 
    count: count } 

end 

=> [{:employeeId =>"898989", :types=>"both", :count=>3}, 
    {:employeeId =>"2423213", :types=>"search", :count=>7}, 
    {:employeeId =>"555555", :types=>"search", :count=>2}, 
    {:employeeId =>"5453454", :types=>"search", :count=>1}, 
    {:employeeId =>"987654321", :types=>"search", :count=>1}] 

Answer 2

Également pas belle, obtiendra aussi t il travail fait, potentiellement plus lisible

hash = {} 
combined.each do |h| 
    employeeId, count, type = h.values_at("employeeId", "count", :type) 
    if hash.include? employeeId 
    hash[employeeId][:count] += count 
    hash[employeeId][:type] = "both" #assumes duplicates can only occur if item is in both lists 
    else 
    hash[employeeId] = { :employeeId => employeeId, :type => type, :count => count } 
    end 
end 
hash.values 

Test:

[{:employeeId=>"898989", :type=>"both", :count=>3}, 
{:employeeId=>"2423213", :type=>"search", :count=>7}, 
{:employeeId=>"555555", :type=>"search", :count=>2}, 
{:employeeId=>"5453454", :type=>"search", :count=>1}, 
{:employeeId=>"987654321", :type=>"search", :count=>1}]