comment trouver l'index de mot dupliquée en python

Question

j'écrire ce code en python

import re 

text = input('please enter text: ') 
word = re.findall('\w+', text) 
len_word = len(word) 
word_pos = [] 

for i in range(len_word): 
    if text.index(word[i]) in word_pos: 
     prev_index = text.index(word[i]) + 1 
     last_index = 0 
     # print('index1: ' , last_index) 
     text = text[prev_index:] 
     # print('new_text: ' , new_text) 
     word_pos.append(text.index(word[i]) + prev_index + last_index) 
     last_index += prev_index 
    else: 
     word_pos.append(text.index(word[i])) 

print(word_pos) 

et la sortie de cette entrée: aa, est: [0, 2], et est correcte, mais ce siguation: aaa, réponse est: [0, 2, 1], je veux voir: [0, 2, 4], et je veux un code dynamique parce que je ne sais pas quand je reçois le mot de duplacated contribution. et s'il y a une solution que je veux obtenir l'index de texte plus dupliquée grâce

Answer 1

Vous pouvez faire quelque chose comme ça:

import re 

text = input('please enter text: ') 
words = re.findall('\w+', text) 
word_pos = [] 
pos = 0 # this will help us track the word's position in the original text 

for i in range(len(words)): 
    word = words[i] 
    pos += text[pos:].index(word) # we use the position of the last word to find the position of the current word 
    if word in words[i+1:] or word in words[:i]: # we have a duplicate so we can append this position 
     word_pos.append(pos) 
     print('{} found at {} in text'.format(word,pos)) 
    pos += 1 

Avec entrée: "a a a a", je reçois le résultat:

please enter text: a a a a a 
a found at 0 in text 
a found at 2 in text 
a found at 4 in text 
a found at 6 in text 
a found at 8 in text 

Answer 2

import re 
text = input('please enter text: ') 
print({word: [w.start() for w in re.finditer(word, text)] for word in text.split()}) 

entrée 1:

please enter text: a a a a 

output: 
{'a': [0, 2, 4, 6]} 

input 2: 
please enter text: Hello Arun Hello man 

output: 
{'Arun': [6], 'Hello': [0, 11], 'man': [17]}