XML Analyse dans le site Web

Question

J'essaye d'analyser une page Web en XML et d'imprimer des données dans mon logcat, mais ma sortie est vide. Ceci est ma structure XML:

<?xml version="1.0"?> 
<FLIGHTS> 
    <FLIGHT airport="b: 3 " 
     logo="IG" 
     code="IG" 
     numero="1234" 
     carrier="AirBerlin" 
     city="NEW YORK" 
     terminal="Terminal A" 
     sched="08:40" 
     expect="09:09" 
     tipo_volo="L" stato="J" 
    </FLIGHT> 
    <FLIGHT airport="c: 3 " 
    .... 
    .....more... 
    </FLIGHT> 
</FLIGHTS> 

et voici mon code Android à l'intérieur AsyncTask:

 @Override 
    protected String doInBackground(String... params) { 

     try { 


      URL url = new URL("http://myurl"); 
      URLConnection conn = url.openConnection(); 

      DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
      DocumentBuilder builder = factory.newDocumentBuilder(); 
      Document doc = builder.parse(conn.getInputStream()); 

      NodeList nodes = doc.getElementsByTagName("FLIGHT"); 
      for (int i = 0; i < nodes.getLength(); i++) { 
       Element element = (Element) nodes.item(i); 
       // NodeList title = element.getElementsByTagName("airport"); 
       // Element line = (Element) title.item(0); 
      //  a.add(line.getTextContent()); 

       Log.d("LOG...", "" + element.getTextContent()); 
      } 
     } catch (Exception e) { 
      e.printStackTrace(); 
     } 

à l'intérieur du AndroidManifest, j'ai la permission d'Internet!

Merci!

Answer 1

Votre exemple de code fonctionne. Java est sensible à la casse. Êtes-vous sûr que votre nom de tag XML est correct?

Voici un exemple de travail en utilisant un exemple XML de W3Schools:

try { 

     URL url = new URL("http://www.w3schools.com/xml/note.xml"); 
     URLConnection conn = url.openConnection(); 

     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder builder = factory.newDocumentBuilder(); 
     Document doc = builder.parse(conn.getInputStream()); 

     NodeList nodes = doc.getElementsByTagName("note"); 
     for (int i = 0; i < nodes.getLength(); i++) { 
      Element element = (Element) nodes.item(i); 
      // NodeList title = element.getElementsByTagName("airport"); 
      // Element line = (Element) title.item(0); 
      // a.add(line.getTextContent()); 

      System.out.println(element.getTextContent()); 
     } 
     } catch (Exception e) { 
     e.printStackTrace(); 
     } 

Et maintenant, en utilisant votre exemple XML et Joop Eggen's réponse:

try { 

    URL url = new URL("http://myurl"); 
    URLConnection conn = url.openConnection(); 

    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
    DocumentBuilder builder = factory.newDocumentBuilder(); 
    Document doc = builder.parse(conn.getInputStream()); 

    NodeList nodes = doc.getElementsByTagName("FLIGHT"); 
    for (int i = 0; i < nodes.getLength(); i++) { 
     Element element = (Element) nodes.item(i); 
     String airport = element.getAttribute("airport"); 

     System.out.println("element " + i + ": airport=" + airport); 
    } 
    } catch (Exception e) { 
    e.printStackTrace(); 
    } 

Exemple utilisant un simple fichier:

test.xml:

<?xml version="1.0"?> 
<FLIGHTS> 
    <FLIGHT airport="b: 3 " logo="IG" code="IG" numero="1234" 
     carrier="AirBerlin" city="NEW YORK" terminal="Terminal A" sched="08:40" 
     expect="09:09" tipo_volo="L" stato="J"> 
    </FLIGHT> 
</FLIGHTS> 

Example.java:

import java.io.File; 
import java.io.FileInputStream; 

import javax.xml.parsers.DocumentBuilder; 
import javax.xml.parsers.DocumentBuilderFactory; 

import org.w3c.dom.Document; 
import org.w3c.dom.Element; 
import org.w3c.dom.NodeList; 

public class Example { 

    public static void main(String[] args) { 
    File f = new File("test.xml"); 
    try { 

     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder builder = factory.newDocumentBuilder(); 
     Document doc = builder.parse(new FileInputStream(f)); 

     NodeList nodes = doc.getElementsByTagName("FLIGHT"); 
     for (int i = 0; i < nodes.getLength(); i++) { 
     Element element = (Element) nodes.item(i); 
     String airport = element.getAttribute("airport"); 

     System.out.println("element " + i + ": airport='" + airport + "'"); 
     } 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    } 
} 

Answer 2

Si le XML était correcte, les attributs sont XXX="..." a différemment:

Element element = (Element) nodes.item(i); 
String airport = element.getAttribute("airport"); 
if (airport != null) { ...