Je dois améliorer ma requête T-SQL afin que je puisse retourner la somme des colonnes

Question

Voici ma requête en cours:

SELECT patron_name, 
    producer.federal_number, 
    hst_number, 
    average_bf_test, 
    (SELECT MAX(s.statement_number) FROM statement s) AS statement_number, 
    (SELECT MAX(s.period_ending) FROM statement s) AS period_ending 
    FROM producer 
    JOIN producer_details ON producer.federal_number = producer_details.federal_number 
    JOIN statement ON producer.patron_number = statement.patron_number 
    WHERE producer.patron_number = @PatronNo 

je dois l'améliorer afin que je puisse récupérer la somme des colonnes d'argent dans ma table 'paiement':

quota_payment (money) 
    total_deductions (money) 
    net_cheque_or_direct_deposit (money) 
    interim_payment (money) 
    final_payment (money) 
    statement_number (int) (FK) (statement_number is the primary key in the statement table) 

Comme par @ la demande de Quassnoi, voici des exemples de données et @ la sortie de la requête de Quassnoi:

producer Table: 
patron_number patron_name federal_number 
20109  A. Beaton 44373 

producer_details Table: 
federal_number hst_number average_bf_test 
44373  R999999999 0.0392 

statement Table: 
statement_number period_ending description   amount_shipped patron_number 
386    2009/07/30  Quota Milk Shipped 32.91   20109 
387    2009/11/30  Quota Milk Shipped 22.34   20109 

payment Table: 
quota_payment total_deductions net_cheque_or_direct_deposit interim_payment 
22872.5800  7526.6500   15345.9300     6520.7000 
18474.3400  4563.2300   13911.1100     3220.3000 
final_payment statement_number 
8825.2300  386 
10690.8100  387   

Ce sont les données renvoyées par la requête @ Quassnoi (à l'origine, la deuxième ligne était NULL pour les colonnes money, mais il s'avère que c'était parce qu'il n'y avait qu'une seule ligne dans la table de paiement à ce moment-là, mais j'ai depuis ajouté une ligne supplémentaire):

patron_name federal_number hst_number average_bf_test  
A. Beaton 44373   R999999999 0.0392       
A. Beaton 44373   R999999999 0.0392        

statement_number period_ending  quota_payment total_deductions 
387    2009/11/30  22872.5800  7526.6500 
387    2009/11/30  18474.3400  4563.2300 

net_cheque_or_direct_deposit interim_payment  final_payment 
15345.9300      6520.7000   8825.2300 
13911.1100      3220.3000   10690.8100 

Voici le recordset souhaité:

patron_name federal_number hst_number average_bf_test  
A. Beaton 44373   R999999999 0.0392 

statement_number period_ending  quota_payment total_deductions 
387    2009/11/30  41346.92  12089.88 


net_cheque_or_direct_deposit interim_payment  final_payment 
29257.04      9741.00    19516.04 

J'ai oublié de mentionner que les valeurs de somme pour les colonnes d'argent devraient être « l'année à ce jour » les valeurs (ce qui signifie des valeurs de l'année précédente ne seraient pas inclus dans les résultats de SUM), ce qui le rend un peu plus compliqué.

Answer 1

Vous pouvez essayez ceci:

Select 
patron_name, 
federal_number, 
hst_number, 
average_bf_test, 
statement_number, 
period_ending, 
sum(quota_payment) as quota_payment, 
sum(total_deductions) as total_deductions, 
sum(net_cheque_or_direct_deposit) as net_cheque_or_direct_deposit, 
sum(interim_payment) as interim_payment, 
sum(final_payment) as final_payment 
from (Quassnois Query here) a 
group by 
patron_name, 
federal_number, 
hst_number, 
average_bf_test, 
statement_number, 
period_ending 

Cela devrait vous aider à obtenir ce que vous voulez en fonction des données que vous avez affichées. Je ne sais pas si cela fait logique dans votre situation, mais cela devrait fonctionner.

Answer 2

Si je comprends ce que vous cherchez à faire, cela devrait fonctionner, ne pas tester la syntaxe ...

en fonction de votre commentaire peut-être votre recherche:

Select a.*,sum(quota_payment) as sum_quota_payment, 
    sum(total_deductions) as sum_total_deductions, 
    sum(net_cheque_or_direct_deposit) as sum_net_cheque, 
    sum(interim_payment) as sum_interim_payment, 
    sum(final_payment) as sum_final_payment 

     from 
     (SELECT patron_name, 
      producer.federal_number, 
      hst_number, 
      average_bf_test, 
      (SELECT MAX(s.statement_number) FROM statement s) AS statement_number, 
      (SELECT MAX(s.period_ending) FROM statement s) AS period_ending 
      FROM producer 
      JOIN producer_details ON producer.federal_number = producer_details.federal_number 
      JOIN statement ON producer.patron_number = statement.patron_number 
      WHERE producer.patron_number = @PatronNo) 
    a left join payment ON a.statement_number = payment.statement_number 

Answer 3

SELECT patron_name, 
     producer.federal_number, 
     hst_number, 
     average_bf_test, 
     (
     SELECT MAX(s.statement_number) 
     FROM statement s 
     ) AS statement_number, 
     (
     SELECT MAX(s.period_ending) 
     FROM statement s 
     ) AS period_ending, 
     sums.* 
FROM producer 
JOIN producer_details 
ON  producer_details.federal_number = producer.federal_number 
JOIN statement so 
ON  so.patron_number = producer.patron_number 
CROSS APPLY 
     (
     SELECT SUM(quota_payment) AS quota_payment, 
       SUM(total_deductions) AS total_deductions, 
       SUM(net_cheque_or_direct_deposit) AS net_cheque_or_direct_deposit, 
       SUM(interim_payment) AS interim_payment, 
       SUM(final_payment) AS final_payment 
     FROM payment p 
     WHERE p.statement_number = so.statement_number 
     ) sums 
WHERE producer.patron_number = @PatronNo