Quelle est la meilleure façon de gérer les exceptions de type SOAP en python

Question

Dans le cas où l'utilisateur entre des données non sur le serveur Web étant accessible par un WSDL, je reçois une erreur:

<?xml version="1.0" encoding="UTF-8"?> 
<SOAP-ENV:Envelope xmlns:ns3="http://www.w3.org/2001/XMLSchema" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns0="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://soap.rpc.jira.atlassian.com" xmlns:ns2="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"> 
    <SOAP-ENV:Header/> 
    <ns2:Body> 
     <ns1:getFieldsForEdit> 
     <in0 xsi:type="ns3:string">FmofSimScl</in0> 
     <in1 xsi:type="ns3:string">QA-65000</in1> 
     </ns1:getFieldsForEdit> 
    </ns2:Body> 
</SOAP-ENV:Envelope> 
<?xml version="1.0" encoding="UTF-8"?> 
<SOAP-ENV:Envelope xmlns:ns3="http://www.w3.org/2001/XMLSchema" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns0="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns1="http://soap.rpc.jira.atlassian.com" xmlns:ns2="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/"> 
    <SOAP-ENV:Header/> 
    <ns2:Body> 
     <ns1:getIssue> 
     <in0 xsi:type="ns3:string">FmofSimScl</in0> 
     <in1 xsi:type="ns3:string">QA-65000</in1> 
     </ns1:getIssue> 
    </ns2:Body> 
</SOAP-ENV:Envelope> 
Traceback (most recent call last): 
    File "/home/qa/jira-test/.hg/check_jira.py", line 64, in <module> 
    main() 
    File "/home/qa/jira-test/.hg/check_jira.py", line 12, in main 
    commit_text_verified = verify_commit_text(os.popen('hg tip --template "{desc}"')) 
    File "/home/qa/jira-test/.hg/check_jira.py", line 35, in verify_commit_text 
    if CheckForJiraIssueRecord(m_args) == 0: 
    File "/home/qa/jira-test/.hg/check_jira.py", line 58, in CheckForJiraIssueRecord 
    issue = com.run(command_name, logger, jira_env, my_args) 
    File "/home/qa/jira-test/.hg/jira.py", line 1367, in run 
    return self.commands[command].dispatch(logger, jira_env, args) 
    File "/home/qa/jira-test/.hg/jira.py", line 75, in dispatch 
    results = self.run(logger, jira_env, args) 
    File "/home/qa/jira-test/.hg/jira.py", line 174, in run 
    logger.error(decode(e)) 
    File "/home/qa/jira-test/.hg/jira.py", line 1434, in decode 
    str = e.faultstring 
AttributeError: 'WebFault' object has no attribute 'faultstring' 
transaction abort! 
rollback completed 
abort: pretxncommit.jira hook exited with status 1 

est-il un moyen pour gérer cela afin que je puisse écrire ma propre chaîne d'erreur, ou un message d'avertissement à la place de tout cela. Si je désactiver stdout je n'obtenir les données xml, mais je reçois encore:

 
transaction abort! 
rollback completed 
abort: pretxncommit.jira hook exited with status 1 

qui est de Mercurial, mais serait agréable d'avoir une une chaîne d'erreur ajoutée à comme warnings.warn ("% s n'existe pas "% ISSUE_ID)

ok, je regardais dans jira.py et changé en ligne 1434: str = e.faultstring à str = e.fault

et a obtenu:

faultcode = "soapenv:Server.userException" 
    faultstring = "com.atlassian.jira.rpc.exception.RemotePermissionException: This issue does not exist or you don't have permission to view it." 
    detail = 
     (detail){ 
     com.atlassian.jira.rpc.exception.RemotePermissionException = "" 
     hostname = "JIRA" 
     } 
} 

Answer 1

il a été fixé dans jira.py: changement qu'il decode fonction:

def decode(e): 
    """Process an exception for useful feedback""" 
    # TODO how to log the fact it is an error, but allow info to be unchanged? 
    # TODO now fault not faultstring? 
    # The faultType class has faultcode, faultstring and detail 
    str = e.fault 
    if str == 'com.atlassian.jira.rpc.exception.RemotePermissionException': 
     return "This issue does not exist or you don't have permission to view it" 
    return e.fault 

au lieu de:

def decode(e): 
    """Process an exception for useful feedback""" 
    # TODO how to log the fact it is an error, but allow info to be unchanged? 
    # TODO now fault not faultstring? 
    # The faultType class has faultcode, faultstring and detail 
    str = e.faultstring 
    if str == 'java.lang.NullPointerException': 
     return "Invalid issue key?" 
    return e.faultstring