Et les deux classes sont les mêmes, par exemple:ne peut pas convertir namespace_something :: some_class à Some_Class
///////////////server.h//////////////
#ifndef SERVER_H
#define SERVER_H
#ifdef WIN32
#ifndef _WIN32_WINNT
#define _WIN32_WINNT 0x0501
#endif
#endif
#include <boost/shared_ptr.hpp>
#include <boost/asio.hpp>
#include <map>
#include "auxiliar.h"
class Client;
namespace Irc
{
typedef boost::shared_ptr<Client> ClientPtr;
typedef std::map<SocketPtr, ClientPtr> ClientsMap;
class Server
{
public:
Server();
~Server();
void start();
void startAccept();
ClientsMap::const_iterator begin() { return m_clients.begin(); }
ClientsMap::const_iterator end() { return m_clients.end(); }
private:
ClientsMap m_clients;
boost::asio::io_service service;
boost::asio::ip::tcp::acceptor* m_acceptor;
};
} //namespace Irc
#endif
/////////////server.cpp////////////////
#include "server.h"
#include "defines.h"
#include "client.h"
Irc::Server::Server()
{
service.run();
}
Irc::Server::~Server()
{
m_clients.clear();
}
void Irc::Server::start()
{
m_acceptor = new boost::asio::ip::tcp::acceptor(service, boost::asio::ip::tcp::endpoint(
boost::asio::ip::tcp::v4(), SERVER_PORT));
}
void Irc::Server::startAccept()
{
SocketPtr s(new boost::asio::ip::tcp::socket(service));
m_acceptor->accept(*s);
Client *client = new Client(s);
client->setIoService(&service);
ClientPtr ptr(client);
m_clients.insert(std::make_pair(s, ptr));
}
Cela produit l'erreur de compilation:
g++.exe -c src/server.cpp -o src/server.o -I"D:/Dev-Cpp/include" -g -ggdb -I"include" -fexpensive-optimizations -O1 D:/Dev-Cpp/include/boost/smart_ptr/shared_ptr.hpp: In constructor
boost::shared_ptr< <template-parameter-1-1> >::shared_ptr(Y*) [with Y = Irc::Client, T = Client]': src/server.cpp:27: instantiated from here D:/Dev-Cpp/include/boost/smart_ptr/shared_ptr.hpp:179: error: cannot convert
Irc::Client*' to `Client*' in initialization
Quelle est l'erreur que vous obtenez? – vitaut
Quel est le message d'erreur? Incluez-vous correctement les deux en-têtes dans le fichier .cpp? – log0
Je ne peux pas reproduire l'erreur. – kennytm