JPA @OneToMany et composite PK

Question

Je travaille sur un projet JPA. J'ai besoin d'utiliser un mapping @OneToMany sur une classe qui a trois clés primaires. Vous pouvez trouver les erreurs et les classes après cela.

javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: 
javax.persistence.PersistenceException 
javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException 
Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. 
Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException 
Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. 
    at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) 
    at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) 
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) 
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) 
    at isd.pacepersistence.common.DataMapper.(Unknown Source) 
    at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) 
    at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) 
    at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) 
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) 
    at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) 
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) 

Voici le code source de mes cours:

Action:

@Entity 
@Table(name="action") 
public class Action { 

    @Id 
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private int num; 

    @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, 
     CascadeType.REFRESH }) 
    @JoinColumn(name="domain_num") 
    private Domain domain; 

    private String name; 
    private String description; 

    @OneToMany 
    @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) 
    private Set<Permission> permissions; 

    public Action() { 
    } 

Permission:

@SuppressWarnings("serial") 
@Entity 
@Table(name="permission") 
public class Permission implements Serializable { 

    @EmbeddedId 
    private PermissionPK primaryKey; 

    @ManyToOne 
    @JoinColumn(name="action_num", insertable=false, updatable=false) 
    private Action action; 

    @ManyToOne 
    @JoinColumn(name="entity_num", insertable=false, updatable=false) 
    private isd.pacepersistence.common.Entity entity; 

    @ManyToOne 
    @JoinColumn(name="class_num", insertable=false, updatable=false) 
    private Clazz clazz; 

    private String kondition; 

    public Permission() { 
    } 

PermissionPK:

@SuppressWarnings("serial") 
@Entity 
@Table(name="permission") 
public class Permission implements Serializable { 

    @EmbeddedId 
    private PermissionPK primaryKey; 

    @ManyToOne 
    @JoinColumn(name="action_num", insertable=false, updatable=false) 
    private Action action; 

    @ManyToOne 
    @JoinColumn(name="entity_num", insertable=false, updatable=false) 
    private isd.pacepersistence.common.Entity entity; 

    @ManyToOne 
    @JoinColumn(name="class_num", insertable=false, updatable=false) 
    private Clazz clazz; 

    private String kondition; 

    public Permission() { 
    } 

Answer 1

Le message d'erreur semble assez clair: vous devez déclarer les trois colonnes de votre PK composite comme @JoinColum et les name et referenceColumnName doivent être spécifiées pour chacune. Je n'ai pas testé la cartographie, mais essayez ceci:

@OneToMany 
@JoinTable(name="permission", joinColumns= { 
    @JoinColumn(name="col1", referencedColumnName="col1", nullable=false, updatable=false), 
    @JoinColumn(name="col2", referencedColumnName="col2", ...), 
    @JoinColumn(name="col3", referencedColumnName="col3", ...) 
}, inverseJoinColumns= { @JoinColumn(name="num") }) 
private Set<Permission> permissions; 

Answer 2

Bonjour,

Après une longue journée de recherche et comment fonctionne JPA @OneToMany avec PK composite, je ne trouve une solution. Pour le faire fonctionner, j'ai utilisé le paramètre mappedBY de @OneToMany. Comme vous pouvez le voir dans l'exemple de code, j'ai mappé l'ensemble des autorisations avec l'attribut attribute de la classe Permission. Et c'est tout! Simple quand vous le savez!

FF

Class Action:

@Entity 
@Table(name="action") 
public class Action { 

    @Id 
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private int num; 

    @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, 
     CascadeType.REFRESH }) 
    @JoinColumn(name="domain_num") 
    private Domain domain; 

    private String name; 
    private String description; 

    @OneToMany(mappedBy="action") 
    private Set<Permission> permissions; 

Permission Classe

@SuppressWarnings("serial") 
@Entity 
@Table(name="permission") 
public class Permission implements Serializable { 

    @EmbeddedId 
    private PermissionPK primaryKey; 

    @ManyToOne 
    @JoinColumn(name="action_num", insertable=false, updatable=false) 
    private Action action;