Comment faire une transition en flex 4 sur un remplissage contenant un dégradé linéaire?

Question

<?xml version="1.0" encoding="utf-8"?> 

<s:Rect id="background" top="0" right="0" bottom="0" left="0" height="30"> 
    <s:fill> 
     <s:SolidColor color="#000000"/> 
    </s:fill> 
    <s:fill.over> 
     <s:LinearGradient rotation="90"> 
      <s:GradientEntry color="#FF5800" alpha="1.0" ratio="0"/> 
      <s:GradientEntry color="#EE0202" alpha="1.0" ratio="1"/> 
     </s:LinearGradient> 
    </s:fill.over> 
    <s:fill.down> 
     <s:LinearGradient rotation="90"> 
      <s:GradientEntry color="#EE0202" alpha="1.0" ratio="0"/> 
      <s:GradientEntry color="#AF0000" alpha="1.0" ratio="1"/> 
     </s:LinearGradient> 
    </s:fill.down> 
</s:Rect> 
<s:RichText id="labelDisplay" paddingLeft="10" paddingRight="10" textAlign="center" fontFamily="Myriad Pro" fontSize="16" tabStops="S0 S50 S100 S150" color="#FFFFFF" y="8" color.over="#000000" tabStops.over="S0 S50 S100 S150" color.down="#000000" tabStops.down="S0 S50 S100 S150" color.disabled="#EE0202" tabStops.disabled="S0 S50 S100 S150" color.up="#EE0202" tabStops.up="S0 S50 S100 S150"> 
    <s:filters> 
     <s:DropShadowFilter includeIn="over" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#FFFFFF" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> 
     <s:DropShadowFilter includeIn="down" blurX="0" blurY="0" distance="1" hideObject="false" inner="false" color="#CCCCCC" strength="1" alpha="1" quality="2" knockout="false" angle="45.0"/> 
     <s:BlurFilter includeIn="disabled" blurX="4.0" blurY="4.0" quality="2"/> 
    </s:filters> 
</s:RichText> 

est ici le code, je voudrais faire une transition en douceur lorsque pénètre dans l'état "sur". de l'aide?

Answer 1

<s:AnimateColor colorTo="0xff0000" target="{targetGradientEntry}"/>