Requête MySQL Union dupliquée/groupe par problème

Question

En savoir plus sur les requêtes UNION - quelle économie de temps - mais vous avez des problèmes avec le regroupement.

J'ai fait la déclaration suivante:

(SELECT `shops`.shpUserAdded AS userName, count(`shops`.shpID) AS shpCount, "" AS prdCount FROM `shops` GROUP BY shpUserAdded ASC) 
UNION 
(SELECT `products`.prdUserAdded AS userName, "" AS shpCount, count(`products`.prdID) AS prdCount FROM `products` GROUP BY prdUserAdded ASC) 

mais cela me donne les résultats de la première requête suivie par les résultats de la deuxième requête, sans combiner les noms d'utilisateur:

userName|merCount|prdCount 
     |  8| 
Jane |  1| 
Derek |  1| 
James |  22| 
     |  |  3 
Jane |  |  4 
Derek |  |  5 
James |  |  21 

J'essayées (mais évidemment eu #1248 - Every derived table must have its own alias):

SELECT userName, shpCount, prdCount FROM 
((SELECT `shops`.shpUserAdded AS userName, count(`shops`.shpID) AS shpCount, "" AS prdCount FROM `shops` GROUP BY shpUserAdded ASC) 
UNION 
(SELECT `products`.prdUserAdded AS userName, "" AS shpCount, count(`products`.prdID) AS prdCount FROM `products` GROUP BY prdUserAdded ASC)) 
GROUP BY userName ASC 

Je ne peux pas sembler comprendre nommer la table dérivée (s) sans effacer les données de la colonne shpCount ou prdCount - des suggestions? Je vais probablement me sentir stupide mais thereyago!

Résolu (vraiment cette fois)! :)

SELECT Users.userName, Products.prdCount, Shops.shpCount FROM 
(
    (
     (SELECT `Shops`.shpAddU AS userName FROM `Shops` GROUP BY shpAddU ASC) 
     UNION 
     (SELECT `Products`.prdAddU AS userName FROM `Products` GROUP BY prdAddU ASC) 
    ) AS Users 
) 
LEFT JOIN 
(SELECT prdAddU AS userName, count(*) AS prdCount FROM `Products` GROUP BY prdAddU) as Products ON Users.userName = Products.userName 
LEFT JOIN 
(SELECT shpAddU AS userName, count(*) AS shpCount FROM `Shops` GROUP BY shpAddU) as Shops ON Users.userName = Shops.userName 

Answer 1

Pas tout est une union - dans ce cas, il est une jointure sur les sous-requêtes:

SELECT shpUserAdded AS userName, merCount, prdCount 
FROM (SELECT shpUserAdded, count(*) AS shpCount FROM shops GROUP BY shpUserAdded ASC) AS s 
JOIN (SELECT prdUserAdded, count(*) AS prdCount FROM products GROUP BY prdUserAdded ASC) AS p 
ON (shpUserAdded = prdUserAdded);