Voici le code que j'ai utilisé pour stocker une image dans ma base de données (SQL Server 2008 R2) en utilisant VB 2010. Les images sont stockées mais le problème est que la clarté de l'image est perdue lors de la récupération et vu dans une boîte d'image.Stockage et récupération d'images dans la base de données
Public Function InsertUpdateImage(ByRef _SqlConnection As System.Data.SqlClient.SqlConnection, ByVal _Image As System.Drawing.Image, ByVal _ImageFormat As System.Drawing.Imaging.ImageFormat) As Integer
Dim _SqlRetVal As Integer = 0
'System.IO.Path.GetFullPath(files(ListView1.SelectedIndices(0))) Give the path for the 'image from listview
Dim str As String = System.IO.Path.GetFullPath(files(ListView1.SelectedIndices(0)))
Dim i As Integer = Len(str)
Dim j As Integer = 0
Dim locstr(i + 10) As Char
i = 0
While i < Len(str)
If str(i) = "\" Then
locstr(j) = "\"
j = j + 1
Else
locstr(j) = str(i)
j = j + 1
End If
i = i + 1
End While
Dim loc As New String(locstr)
MsgBox(loc)
' lets add this record to database
Dim _SqlCommand As New System.Data.SqlClient.SqlCommand("insert into maindb(photo,name,location) values(@image,'" + System.IO.Path.GetFileName(files(ListView1.SelectedIndices(0))) + "','" + loc + "')", _SqlConnection)
' Convert image to memory stream
Dim _MemoryStream As New System.IO.MemoryStream()
_Image.Save(_MemoryStream, _ImageFormat)
' Add image as SQL parameter
Dim _SqlParameter As New System.Data.SqlClient.SqlParameter("@image", SqlDbType.Image)
_SqlParameter.Value = _MemoryStream.ToArray()
_SqlCommand.Parameters.Add(_SqlParameter)
' Executes a Transact-SQL statement against the connection
' and returns the number of rows affected.
_SqlRetVal = _SqlCommand.ExecuteNonQuery()
Console.Write(_SqlRetVal)
' Dispose command
_SqlCommand.Dispose()
_SqlCommand = Nothing
' Error occurred while trying to execute reader
' send error message to console (change below line to customize error handling)
Return _SqlRetVal
End Function
Je pense que vous devez inclure plus d'informations sur la façon dont vous récupérez l'image et l'afficher. –