Python - sauter des lignes vides et imprimer 3 lignes après un match

Question

Je ne peux pas sembler ignorer la ligne- vide

import re 

with open('list.txt', 'r+') as f: 
     line = f.readline() 
     while(line): 
     if line != ['']: 
      if " win" in line: 
       print(f.readline(),end="") 
      # 2nd line 
       print(f.readline(),end="") 
      # 3rd line 
       print(f.readline(),end="") 
      line = f.readline() 

list.txt

You tell yourself... 
That should have been my big win. 

It's a kick in the gut. 
Knowing in your heart the reason. 
While you're stuck on the outside. 
Grinning. 

Elle imprime avec comme ci-dessous instead- Lines apparaît après une ligne vide.

It's a kick in the gut. Knowing in your heart the reason.

Answer 1

Vous devez lui dire de sauter des lignes vides lors de l'impression (les commentaires sont en ligne):

if " win" in line: 
    for _ in range(3): # do three times 
     line = f.readline() # get next line 
     # skip blank lines 
     while not line.strip(): 
      line = f.readline() 
     # Print the non-blank line 
     print(line, end="") 
line = f.readline()