Obtenez le minimum et le maximum de temps. Fom enregistrement de présence dans Sql Server

Question

Je travaille sur le système de présence, et au-dessous mes données dans la base de données du serveur SQL

|EmpCode|Date  |WorkDate |CheckIn |CheckOut |TotalTime 
|143 |2017-02-13 |2017-02-13 |20:09:02 |22:38:50 |2.496666000 
|143 |2017-02-13 |2017-02-13 |22:59:19 |23:18:15 |0.315555000 
|143 |2017-02-13 |2017-02-13 |23:33:47 |05:04:24 |5.510277000 
|143 |2017-02-14 |2017-02-13 |02:52:38 |05:12:04 |2.323888000 
|143 |2017-02-14 |2017-02-14 |20:09:26 |21:59:27 |1.833611000 
|143 |2017-02-14 |2017-02-14 |22:30:10 |22:49:26 |0.321111000 
|143 |2017-02-15 |2017-02-14 |05:05:05 |05:08:13 |0.052222000 

- Je veux la sortie comme

|EmpCode|wrk  |InTime  |OutTime |TotalTime 
|143 |2017-02-13 |08:09:02 PM|05:12:04 AM|10:38:00 
|143 |2017-02-14 |08:09:26 PM|05:08:13 AM|02:12:00 

Answer 1

En supposant que vous voulez ceux qui sont spécifiques formats pour les temps:

rextester: http://rextester.com/FUW31296

create table t (
    EmpCode int 
    , Date datetime 
    , WorkDate datetime 
    , CheckIn datetime 
    , CheckOut datetime 
    , TotalTime decimal(19, 9)) 

insert into t values 
(143,'2017-02-13','2017-02-13','20:09:02','22:38:50',2.496666000) 
,(143,'2017-02-13','2017-02-13','22:59:19','23:18:15',0.315555000) 
,(143,'2017-02-13','2017-02-13','23:33:47','05:04:24',5.510277000) 
,(143,'2017-02-14','2017-02-13','02:52:38','05:12:04',2.323888000) 
,(143,'2017-02-14','2017-02-14','20:09:26','21:59:27',1.833611000) 
,(143,'2017-02-14','2017-02-14','22:30:10','22:49:26',0.321111000) 
,(143,'2017-02-15','2017-02-14','05:05:05','05:08:13',0.052222000); 

requête:

select 
    EmpCode 
    , wrk  = convert(varchar(10),WorkDate,120) 
    , InTime = format(cast(min(Date + CheckIn) as datetime), 'hh:mm:ss tt') 
    , OutTime = format(cast(max(Date + CheckOut) as datetime), 'hh:mm:ss tt') 
    , TotalTime = format(dateadd(minute,sum(TotalTime)*60,0), 'HH:mm:ss') 
from t 
group by 
    EmpCode 
    , WorkDate 

résultats:

+---------+------------+-------------+-------------+-----------+ 
| EmpCode | wrk  | InTime | OutTime | TotalTime | 
+---------+------------+-------------+-------------+-----------+ 
|  143 | 2017-02-13 | 08:09:02 PM | 05:12:04 AM | 10:38:00 | 
|  143 | 2017-02-14 | 08:09:26 PM | 05:08:13 AM | 02:12:00 | 
+---------+------------+-------------+-------------+-----------+ 

Answer 2

select EmpCode, WorkDate as wrk, min(InTime) as InTime, max(OutTime) as OutTime, Sum(TotalTime) as TotalTime 
from yourtable 
group by EmpCode, WorkDate 

vous donnera le plus petit InTime, bigest OutTime et la TotalTime totale de yourtable par utilisateur et par jour.

Answer 3

select * 
,  datediff(minute, first_in, last_out) as Totaltime 
from (
     select emp_reader_id 
     ,  min(case when Event_entry.event_entry_name = 'IN' then trnevents.DT end) as Intime 
     ,  max(case when Event_entry.event_entry_name = 'OUT' then trnevents.DT end) as Outtime 
     ,  cast(min(trnevents.DT) as date) as date 
     from trnevents inner join Event_entry on trnevents.EventCatId=Event_entry.EventCatId 
     group by 
       emp_reader_id 
     ,  cast(trnevents.DT as date) 
     ) as SubQueriesMustBeNamed